(-3)=x^2+2x-1

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Solution for (-3)=x^2+2x-1 equation: 



(-3)=x^2+2x-1

We move all terms to the left:

(-3)-(x^2+2x-1)=0

We add all the numbers together, and all the variables

-(x^2+2x-1)-3=0

We get rid of parentheses

-x^2-2x+1-3=0

We add all the numbers together, and all the variables

-1x^2-2x-2=0

a = -1; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·(-1)·(-2)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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